Philosoraptor [he/him, comrade/them]

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Joined 6 years ago
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Cake day: August 3rd, 2020

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  • Ah, I misunderstood your question. Yeah, most of the overall energy goes into heat for sure. Since the accelerator is using massive particles in its collision, it’s probably not right to say that energy is being transformed into mass: the total mass of the system is conserved, and you’re just “whacking” an antiproton off the iridium nucleus via inelastic scattering. You could get that kind of transfer if the colliding particle were massless (like a photon), which happens with cosmic rays sometimes. It’s harder to control in a number of different respects though, and you’re not guaranteed to get the kind of anti-particle you want. By using a proton, we can guarantee we get the flavor we want, since all the quantum numbers are also conserved.


  • If you mean does it cost energy to produce it, then yes an incredible amount. The only way we have of making it is to smash particles together in an accelerator at enormous speeds. The LHC at CERN uses protons and, for this kind of experiment, probably some kind of dense metallic atom like iridium (though I don’t know off the top of my head). That takes a truly incredible amount of power to run–something like half the power consumption of a small city. That energy doesn’t disappear of course: some of it goes into the beam, but most of it goes into operating the magnets used in acceleration. The actual creation of the particle anti-particle pair conserves energy just like everything else.


  • Generally yes, they’re always produced in pairs (which is why it’s so hard to get them to stick around, as they tend to more-or-less instantly annihilate each other). There are some exotic exceptions to this mostly involving neutrinos that we don’t fully understand yet, but this kind of an experiment will generally get you a particle/anti-particle pair. When you depict the process with a Feynman diagram, the symmetry is really evident, which is part of why they’re such great representational tools for this kind of interaction.